What is expand ((x-1)log_{2}(x))/(1+x) ?

The solution to expand ((x-1)log_{2}(x))/(1+x) is (xlog_{2}(x)-log_{2}(x))/(1+x)

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expand ((x-1)log_{2}(x))/(1+x)

expand

\frac{( x - 1 ) lo g _{2} ( x )}{1 + x}

\frac{x lo g _{2} ( x ) - lo g _{2} ( x )}{1 + x}

Solution steps

\frac{( x - 1 ) lo g _{2} ( x )}{1 + x}

Expand

(x - 1) lo g_{2} (x) : x lo g_{2} (x) - lo g_{2} (x)

= \frac{x lo g _{2} ( x ) - lo g _{2} ( x )}{1 + x}

\frac{3 ( 1 + 5 )}{2}

(\frac{( x + 1 ) ( x ) ( x - 2 )}{- 2}) \cdot 3

\frac{9 ( x ^{10} - 1 )}{5}

\frac{10 x ^{2} + 10}{( x + 1 ) ^{4}}

\frac{x ( 128 x ^{2} - 735 x - 264 )}{64 ( x - 4 ) ^{2}}

What is expand ((x-1)log_{2}(x))/(1+x) ?
The solution to expand ((x-1)log_{2}(x))/(1+x) is (xlog_{2}(x)-log_{2}(x))/(1+x)