What is expand (e^{-4x}(e^{8x}-1))/2 ?

The solution to expand (e^{-4x}(e^{8x}-1))/2 is (e^{4x})/2-(e^{-4x})/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (e^{-4x}(e^{8x}-1))/2

expand

\frac{e ^{- 4 x} ( e ^{8 x} - 1 )}{2}

\frac{e ^{4 x}}{2} - \frac{e ^{- 4 x}}{2}

Solution steps

\frac{e ^{- 4 x} ( e ^{8 x} - 1 )}{2}

Expand

e^{- 4 x} (e^{8 x} - 1) : e^{4 x} - e^{- 4 x}

= \frac{e ^{4 x} - e ^{- 4 x}}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{4 x} - e ^{- 4 x}}{2} = \frac{e ^{4 x}}{2} - \frac{e ^{- 4 x}}{2}

= \frac{e ^{4 x}}{2} - \frac{e ^{- 4 x}}{2}

\frac{1. 1 ^{2}}{- 1.1 + 1}

(2 x^{3} y^{2} + 4 x^{2} y + 2 x y^{2} + x y^{4} + 2 y) \cdot e^{x^{2}}

\frac{2}{3} - \frac{1}{3}

\frac{d ^{2}}{d x ^{2}} ((y) (12) (5 x^{2} - 1) (x^{2} - 1))

- e^{an} (e^{- x n} - e^{- an})

What is expand (e^{-4x}(e^{8x}-1))/2 ?
The solution to expand (e^{-4x}(e^{8x}-1))/2 is (e^{4x})/2-(e^{-4x})/2