What is expand (p(1-p)(n-1))/n ?

The solution to expand (p(1-p)(n-1))/n is p-p/n-p^2+(p^2)/n

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expand (p(1-p)(n-1))/n

expand

\frac{p ( 1 - p ) ( n - 1 )}{n}

p - \frac{p}{n} - p^{2} + \frac{p ^{2}}{n}

Solution steps

\frac{p ( 1 - p ) ( n - 1 )}{n}

Expand

p (1 - p) (n - 1) : n p - p - n p^{2} + p^{2}

= \frac{n p - p - n p ^{2} + p ^{2}}{n}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n p - p - n p ^{2} + p ^{2}}{n} = \frac{n p}{n} - \frac{p}{n} - \frac{n p ^{2}}{n} + \frac{p ^{2}}{n}

= \frac{n p}{n} - \frac{p}{n} - \frac{n p ^{2}}{n} + \frac{p ^{2}}{n}

Cancel

\frac{n p}{n} : p

= p - \frac{p}{n} - \frac{n p ^{2}}{n} + \frac{p ^{2}}{n}

Cancel

\frac{n p ^{2}}{n} : p^{2}

= p - \frac{p}{n} - p^{2} + \frac{p ^{2}}{n}

, - 4 (7 n - 5) + 4 n

\frac{2 x + 3}{( x ^{2} + 3 x ) ^{2}}

lo g_{n} (\frac{mn}{n + 1})

\frac{1}{( e ^{2 A T} - 1 ) ( e ^{- 2 A T} - 1 )}

What is expand (p(1-p)(n-1))/n ?
The solution to expand (p(1-p)(n-1))/n is p-p/n-p^2+(p^2)/n