What are the solutions to the equation x^2+3x-2=0 ?

The solutions to the equation x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2

Find the zeros of x^2+3x-2=0

The zeros of x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2

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x^{2} + 3 x - 2 = 0

x = \frac{- 3 + 17}{2}, x = \frac{- 3 - 17}{2}

Solution steps

x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 2) = 17

x_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 17}{2 \cdot 1}, x_{2} = \frac{- 3 - 17}{2 \cdot 1}

x = \frac{- 3 + 17}{2 \cdot 1} : \frac{- 3 + 17}{2}

x = \frac{- 3 - 17}{2 \cdot 1} : \frac{- 3 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 17}{2}, x = \frac{- 3 - 17}{2}

x + 6 (\frac{1}{3} x + 2) = 6

4 x^{2} + 64

2 y^{2} + 14 y = - 19

4 x + 8 = 20

(- 4)^{- 6} (- 4)^{7}

What are the solutions to the equation x^2+3x-2=0 ?
The solutions to the equation x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2
Find the zeros of x^2+3x-2=0
The zeros of x^2+3x-2=0 are x=(-3+sqrt(17))/2 ,x=(-3-sqrt(17))/2