What is expand ln(x^3+2)(x^2+3) ?

The solution to expand ln(x^3+2)(x^2+3) is x^2ln(x^3+2)+3ln(x^3+2)

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expand ln(x^3+2)(x^2+3)

expand

ln (x^{3} + 2) (x^{2} + 3)

x^{2} ln (x^{3} + 2) + 3 ln (x^{3} + 2)

Solution steps

ln (x^{3} + 2) (x^{2} + 3)

Apply the distributive law:

a (b + c) = ab + a c

a = ln (x^{3} + 2), b = x^{2}, c = 3

= ln (x^{3} + 2) x^{2} + ln (x^{3} + 2) \cdot 3

= x^{2} ln (x^{3} + 2) + 3 ln (x^{3} + 2)

π (162 - \frac{112 2}{15})

(2 - \frac{1}{a})^{2} + (2 + \frac{1}{a})^{2^{^{'}}}

7 (ln (6) + 1)

(e^{- x} + 2)^{2}

\frac{k}{( J s + b ) ( L s + R ) + k ^{2}}

What is expand ln(x^3+2)(x^2+3) ?
The solution to expand ln(x^3+2)(x^2+3) is x^2ln(x^3+2)+3ln(x^3+2)