What is expand ((x+13)(3y-2))/3 ?

The solution to expand ((x+13)(3y-2))/3 is xy-(2x)/3+13y-26/3

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expand ((x+13)(3y-2))/3

expand

\frac{( x + 13 ) ( 3 y - 2 )}{3}

x y - \frac{2 x}{3} + 13 y - \frac{26}{3}

Solution steps

\frac{( x + 13 ) ( 3 y - 2 )}{3}

Expand

(x + 13) (3 y - 2) : 3 x y - 2 x + 39 y - 26

= \frac{3 x y - 2 x + 39 y - 26}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x y - 2 x + 39 y - 26}{3} = \frac{3 x y}{3} - \frac{2 x}{3} + \frac{39 y}{3} - \frac{26}{3}

= \frac{3 x y}{3} - \frac{2 x}{3} + \frac{39 y}{3} - \frac{26}{3}

Divide the numbers:

\frac{3}{3} = 1

= x y - \frac{2 x}{3} + \frac{39 y}{3} - \frac{26}{3}

Divide the numbers:

\frac{39}{3} = 13

= x y - \frac{2 x}{3} + 13 y - \frac{26}{3}

\frac{1}{4 ( c ^{3} + d ^{2} )}

\frac{S}{( S ^{2} + 1 ) ( S - 1 )}

\frac{4 a ^{2} - b ^{2} - 2 a + b}{( 2 a + b ) ^{2} - 1}

(1 - w - w^{2})^{5}

2 c (4 x y^{3} \frac{d y}{d x} + y^{4})

What is expand ((x+13)(3y-2))/3 ?
The solution to expand ((x+13)(3y-2))/3 is xy-(2x)/3+13y-26/3