What is expand 1/3 (-3)^3+1/2 (-3)^2-2(-3) ?

The solution to expand 1/3 (-3)^3+1/2 (-3)^2-2(-3) is 3/2

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expand 1/3 (-3)^3+1/2 (-3)^2-2(-3)

expand

\frac{1}{3} (- 3)^{3} + \frac{1}{2} (- 3)^{2} - 2 (- 3)

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\frac{1}{3} (- 3)^{3} + \frac{1}{2} (- 3)^{2} - 2 (- 3)

Apply rule

- (- a) = a

= \frac{1}{3} (- 3)^{3} + \frac{1}{2} (- 3)^{2} + 2 \cdot 3

\frac{1}{3} (- 3)^{3} = - 9

= - 9 + (- 3)^{2} \frac{1}{2} + 2 \cdot 3

\frac{1}{2} (- 3)^{2} = \frac{9}{2}

2 \cdot 3 = 6

= - 9 + \frac{9}{2} + 6

Add/Subtract the numbers:

- 9 + 6 = - 3

= \frac{9}{2} - 3

Convert element to fraction:

3 = \frac{3 \cdot 2}{2}

= - \frac{3 \cdot 2}{2} + \frac{9}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 2 + 9}{2}

- 3 \cdot 2 + 9 = 3

= \frac{3}{2}

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What is expand 1/3 (-3)^3+1/2 (-3)^2-2(-3) ?
The solution to expand 1/3 (-3)^3+1/2 (-3)^2-2(-3) is 3/2