What is expand (16b^2-128b-1304)/((b-4)^2) ?

The solution to expand (16b^2-128b-1304)/((b-4)^2) is (16b^2-128b-1304)/(b^2-8b+16)

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expand (16b^2-128b-1304)/((b-4)^2)

expand

\frac{16 b ^{2} - 128 b - 1304}{( b - 4 ) ^{2}}

\frac{16 b ^{2} - 128 b - 1304}{b ^{2} - 8 b + 16}

Solution steps

\frac{16 b ^{2} - 128 b - 1304}{( b - 4 ) ^{2}}

(b - 4)^{2} = b^{2} - 8 b + 16

= \frac{16 b ^{2} - 128 b - 1304}{b ^{2} - 8 b + 16}

ln (y - 46.63 (e^{- k (x - o)}))

\frac{x ^{4} + x ^{3} + x ^{2} - x}{( x + 1 ) ( x ^{2} + 1 )}

\frac{6 s ^{2} - 13 s + 2}{s ( s ^{2} + 2 s + 5 )}

\frac{1 - t}{( 1 - t ( 1 + x ) ) ^{2}}

\frac{1}{( 1 + 2 m ) ^{3}}

What is expand (16b^2-128b-1304)/((b-4)^2) ?
The solution to expand (16b^2-128b-1304)/((b-4)^2) is (16b^2-128b-1304)/(b^2-8b+16)