What is the answer to ((8-x))/(25)+((17-x))/(140)-((x))/(10)=0 ?

The answer to ((8-x))/(25)+((17-x))/(140)-((x))/(10)=0 is x=3

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((8-x))/(25)+((17-x))/(140)-((x))/(10)=0

\frac{( 8 - x )}{25} + \frac{( 17 - x )}{140} - \frac{( x )}{10} = 0

x = 3

Solution steps

\frac{( 8 - x )}{25} + \frac{( 17 - x )}{140} - \frac{( x )}{10} = 0

\frac{8 - x}{25} + \frac{17 - x}{140} - \frac{x}{10} = 0

Multiply by LCM

28 (- x + 8) + 5 (- x + 17) - 70 x = 0

Expand

28 (- x + 8) + 5 (- x + 17) - 70 x : - 103 x + 309

- 103 x + 309 = 0

Move

309

to the right side

- 103 x = - 309

Divide both sides by

- 103

x = 3

x (5 x + 6) = 7

x + 11 = 3 x + 1

10 - x = \frac{7 x}{6} + \frac{1}{4}

x^{2} + 4 x + 9 < 0

x^{3} - 8

What is the answer to ((8-x))/(25)+((17-x))/(140)-((x))/(10)=0 ?
The answer to ((8-x))/(25)+((17-x))/(140)-((x))/(10)=0 is x=3
Solve for x: ((8-x))/(25)+((17-x))/(140)-((x))/(10)=0
The solution is x=3