What is expand-2(e^xsin(e^x)+cos(e^x))+4e^{-x} ?

The solution to expand-2(e^xsin(e^x)+cos(e^x))+4e^{-x} is -2e^xsin(e^x)-2cos(e^x)+4e^{-x}

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expand-2(e^xsin(e^x)+cos(e^x))+4e^{-x}

expand

- 2 (e^{x} sin (e^{x}) + cos (e^{x})) + 4 e^{- x}

- 2 e^{x} sin (e^{x}) - 2 cos (e^{x}) + 4 e^{- x}

Solution steps

- 2 (e^{x} sin (e^{x}) + cos (e^{x})) + 4 e^{- x}

Expand

- 2 (e^{x} sin (e^{x}) + cos (e^{x})) : - 2 e^{x} sin (e^{x}) - 2 cos (e^{x})

= - 2 e^{x} sin (e^{x}) - 2 cos (e^{x}) + 4 e^{- x}

(- 1, 0) y (- 1, - 4)

\frac{11}{8 ( x - 4 )} + \frac{5}{8 ( x + 4 )}

\frac{4 x ^{2}}{( 1 - x ^{2} ) ^{2}}

\frac{( ( L + d - x ) ^{2} - x )}{( ( ( L + d - x ) ^{2} - x ) ^{2} + h ^{2} )}

\frac{1}{( s + 1 ) ^{2} \cdot ( s - 2 )}

What is expand-2(e^xsin(e^x)+cos(e^x))+4e^{-x} ?
The solution to expand-2(e^xsin(e^x)+cos(e^x))+4e^{-x} is -2e^xsin(e^x)-2cos(e^x)+4e^{-x}