What is expand (-2x^2-1)/((x^2+1)^{5/2)} ?

The solution to expand (-2x^2-1)/((x^2+1)^{5/2)} is -(2x^2)/((x^2+1)^{5/2)}-1/((x^2+1)^{5/2)}

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expand (-2x^2-1)/((x^2+1)^{5/2)}

expand

\frac{- 2 x ^{2} - 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

- \frac{2 x ^{2}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} - \frac{1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

Solution steps

\frac{- 2 x ^{2} - 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 x ^{2} - 1}{( x ^{2} + 1 ) ^{\frac{5}{2}}} = - \frac{2 x ^{2}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} - \frac{1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

= - \frac{2 x ^{2}}{( x ^{2} + 1 ) ^{\frac{5}{2}}} - \frac{1}{( x ^{2} + 1 ) ^{\frac{5}{2}}}

(e^{x} + 1) (e^{- x} + 1)

\frac{( x ^{2} + 1 - x ^{3} ) ( x ^{3} + 1 - x ^{2} )}{1 - x ^{2} - x ^{3}}

(2 x + 3 y = 1, 8) - (3 x + 2 y = 21)

- \frac{18}{( x + 1 ) ^{4}}

\frac{x ( x ^{2} + 4 x )}{5}

What is expand (-2x^2-1)/((x^2+1)^{5/2)} ?
The solution to expand (-2x^2-1)/((x^2+1)^{5/2)} is -(2x^2)/((x^2+1)^{5/2)}-1/((x^2+1)^{5/2)}