What is expand e^{t-3}u(-t+3) ?

The solution to expand e^{t-3}u(-t+3) is -e^{t-3}tu+3e^{t-3}u

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expand e^{t-3}u(-t+3)

expand

e^{t - 3} u (- t + 3)

- e^{t - 3} t u + 3 e^{t - 3} u

Solution steps

e^{t - 3} u (- t + 3)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{t - 3} u, b = - t, c = 3

= e^{t - 3} u (- t) + e^{t - 3} u \cdot 3

Apply minus-plus rules

+ (- a) = - a

= - e^{t - 3} t u + 3 e^{t - 3} u

x^{2} (3 x^{3} - 2)^{4} d x

\frac{4}{( x + 1 ) ( x + 5 ) ( s - 3 )}

x^{2} y^{''} (x) + x y^{'} (x) + (x^{2} - \frac{1}{4}) y

\frac{( x - 2 ) ( - 3 x + 180 )}{x}

\frac{( s + 1 )}{( s + 2 ) \cdot ( s + 4 )}

What is expand e^{t-3}u(-t+3) ?
The solution to expand e^{t-3}u(-t+3) is -e^{t-3}tu+3e^{t-3}u