What is expand 4sin(2)(pi-θ) ?

The solution to expand 4sin(2)(pi-θ) is 4pisin(2)-4sin(2)θ

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expand 4sin(2)(pi-θ)

expand

4 sin (2) (π - θ)

4 π sin (2) - 4 sin (2) θ

Solution steps

4 sin (2) (π - θ)

Apply the distributive law:

a (b - c) = ab - a c

a = 4 sin (2), b = π, c = θ

= 4 sin (2) π - 4 sin (2) θ

= 4 π sin (2) - 4 sin (2) θ

\frac{1 - n ^{2} x ^{2}}{( 1 + n ^{2} x ^{2} ) ^{2}}

\frac{x ( x - 4 )}{( x + 6 ) ( x - 2 )}

\frac{d x}{( x - 3 ) ^{3}}

- \frac{2 ( 5 x ^{2} + 52 x - 34 )}{( x + 10 ) ( x + 1 ) ( x - 2 )}

(y e^{x y} - 2 y^{3}) d x - (6 x y^{2} + 2 y - x e^{x y}) d y

What is expand 4sin(2)(pi-θ) ?
The solution to expand 4sin(2)(pi-θ) is 4pisin(2)-4sin(2)θ