What is expand log_{10}(112)-0.49log_{10}(500) ?

The solution to expand log_{10}(112)-0.49log_{10}(500) is 0.72672…

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expand log_{10}(112)-0.49log_{10}(500)

expand

lo g_{10} (112) - 0.49 lo g_{10} (500)

0.72672 \dots

Solution steps

lo g_{10} (112) - 0.49 lo g_{10} (500)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

0.49 lo g_{10} (500) = lo g_{10} (50 0^{0.49})

= lo g_{10} (112) - lo g_{10} (50 0^{0.49})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (112) - lo g_{10} (50 0^{0.49}) = lo g_{10} (\frac{112}{50 0 ^{0.49}})

= lo g_{10} (\frac{112}{50 0 ^{0.49}})

Expand

\frac{112}{50 0 ^{0.49}} : 5.32994 \dots

= lo g_{10} (5.32994 \dots)

Refine to a decimal form

= 0.72672 \dots

(x + y) e^{x^{2} + y^{3}}

- \frac{7}{x ( x + 2 ) ^{2}}

2 (64 x^{3} + 96 x^{2} + 56 x + 16)^{2}

(\frac{cos ( x )}{x} - ln (sin (t)))^{2}

\frac{x - 3}{( x + 2 ) ( x - 2 )}

What is expand log_{10}(112)-0.49log_{10}(500) ?
The solution to expand log_{10}(112)-0.49log_{10}(500) is 0.72672…