What is expand e^{2t}(2-t-2e^{-t}) ?

The solution to expand e^{2t}(2-t-2e^{-t}) is 2e^{2t}-e^{2t}t-2e^t

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expand e^{2t}(2-t-2e^{-t})

expand

e^{2 t} (2 - t - 2 e^{- t})

2 e^{2 t} - e^{2 t} t - 2 e^{t}

Solution steps

e^{2 t} (2 - t - 2 e^{- t})

Distribute parentheses

= e^{2 t} \cdot 2 + e^{2 t} (- t) + e^{2 t} (- 2 e^{- t})

Apply minus-plus rules

+ (- a) = - a

= 2 e^{2 t} - e^{2 t} t - 2 e^{2 t} e^{- t}

2 e^{2 t} e^{- t} = 2 e^{t}

= 2 e^{2 t} - e^{2 t} t - 2 e^{t}

((x - 2 L)^{2})^{2}

25 π (2 - \frac{x}{4})^{2}

\frac{- 5}{( 3 - 2 ) ^{2}}

5 (\frac{d ^{3}}{d t ^{3}} (t^{3})) (1 - sin (4 t))

- 13 (x + 2 π)

What is expand e^{2t}(2-t-2e^{-t}) ?
The solution to expand e^{2t}(2-t-2e^{-t}) is 2e^{2t}-e^{2t}t-2e^t