What is expand ((x+3)^2)/(x-5) ?

The solution to expand ((x+3)^2)/(x-5) is (x^2+6x+9)/(x-5)

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expand ((x+3)^2)/(x-5)

expand

\frac{( x + 3 ) ^{2}}{x - 5}

\frac{x ^{2} + 6 x + 9}{x - 5}

Solution steps

\frac{( x + 3 ) ^{2}}{x - 5}

(x + 3)^{2} = x^{2} + 6 x + 9

= \frac{x ^{2} + 6 x + 9}{x - 5}

\frac{9 ( x + 2 ) ^{3} ( x - 6 )}{2 ( x - 7 ) ^{\frac{1}{2}}}

\frac{x - a}{( x ^{2} - 2 x ) ( x + b )}

\frac{( 5 x ^{2} + 5 ) ( 3 x + 1 )}{8 x - 1}

\frac{5 ( 15 + 1205 )}{49}

\frac{{ [ arcsin ( x ) ] ^{3} + ( arccos ( x ) ) ^{3} }}{π ^{3}}

What is expand ((x+3)^2)/(x-5) ?
The solution to expand ((x+3)^2)/(x-5) is (x^2+6x+9)/(x-5)