What is expand ((y^2+2y-3)^2)/(16(y+1)^2) ?

The solution to expand ((y^2+2y-3)^2)/(16(y+1)^2) is (y^4+4y^3-2y^2-12y+9)/(16y^2+32y+16)

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expand ((y^2+2y-3)^2)/(16(y+1)^2)

expand

\frac{( y ^{2} + 2 y - 3 ) ^{2}}{16 ( y + 1 ) ^{2}}

\frac{y ^{4} + 4 y ^{3} - 2 y ^{2} - 12 y + 9}{16 y ^{2} + 32 y + 16}

Solution steps

\frac{( y ^{2} + 2 y - 3 ) ^{2}}{16 ( y + 1 ) ^{2}}

(y + 1)^{2} = y^{2} + 2 y + 1

= \frac{( y ^{2} + 2 y - 3 ) ^{2}}{16 ( y ^{2} + 2 y + 1 )}

(y^{2} + 2 y - 3)^{2} = y^{4} + 4 y^{3} - 2 y^{2} - 12 y + 9

= \frac{y ^{4} + 4 y ^{3} - 2 y ^{2} - 12 y + 9}{16 ( y ^{2} + 2 y + 1 )}

Expand

16 (y^{2} + 2 y + 1) : 16 y^{2} + 32 y + 16

= \frac{y ^{4} + 4 y ^{3} - 2 y ^{2} - 12 y + 9}{16 y ^{2} + 32 y + 16}

\frac{b ^{2}}{( n - 1 ) \cdot s ^{2}}

(- 8 t^{3} + 68 t^{2} - 204 t + 207) \cdot (- 1.2)

f (s) [(1 + e^{2 t})^{2}]

\frac{3 ( x + y )}{x}

\frac{( 4 t + 1 ) y ^{'} ( t )}{t}

What is expand ((y^2+2y-3)^2)/(16(y+1)^2) ?
The solution to expand ((y^2+2y-3)^2)/(16(y+1)^2) is (y^4+4y^3-2y^2-12y+9)/(16y^2+32y+16)