What is expand (2+3i)(2-3i)' ?

The solution to expand (2+3i)(2-3i)' is 2(2-3i)'+3i(2-3i)'

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expand (2+3i)(2-3i)'

expand

(2 + 3 i) (2 - 3 i)^{'}

2 (2 - 3 i)' + 3 i (2 - 3 i)'

Solution steps

(2 + 3 i) (2 - 3 i)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (2 - 3 i)^{'}, b = 2, c = 3 i

= (2 - 3 i)^{^{'}} 2 + (2 - 3 i)^{^{'}} 3 i

= 2 (2 - 3 i)^{^{'}} + 3 i (2 - 3 i)^{^{'}}

x (1 - x - x^{3} + x^{4})^{2}

cos (3 t) U (t - \frac{7 π}{2})

V (2, - 3) F (2, - 4)

(4 m + 2 n = 70,) (- 3 m + 4 n = 30)

\frac{1}{( x + n + 1 ) ^{2}}

What is expand (2+3i)(2-3i)' ?
The solution to expand (2+3i)(2-3i)' is 2(2-3i)'+3i(2-3i)'