What is expand (2xy)+(y^2-x^2-4)y'(x) ?

The solution to expand (2xy)+(y^2-x^2-4)y'(x) is 2xy+y'(x)y^2-x^2y'(x)-4y'(x)

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expand (2xy)+(y^2-x^2-4)y'(x)

expand

(2 x y) + (y^{2} - x^{2} - 4) y^{'} (x)

2 x y + y' (x) y^{2} - x^{2} y' (x) - 4 y' (x)

Solution steps

(2 x y) + (y^{2} - x^{2} - 4) y^{'} (x)

Expand

y^{'} (x) (y^{2} - x^{2} - 4) : y^{'} (x) y^{2} - x^{2} y^{'} (x) - 4 y^{'} (x)

= (2 x y) + y^{'} (x) y^{2} - x^{2} y^{'} (x) - 4 y^{'} (x)

Remove parentheses:

(a) = a

= 2 x y + y^{^{'}} (x) y^{2} - x^{2} y^{^{'}} (x) - 4 y^{^{'}} (x)

\frac{x - 1}{( x + 1 ) ( x - 2 )}

4 \cdot 3482

(1 - \frac{1}{x ^{2}})^{''} \cdot (2 + x) + (1 - \frac{1}{x ^{2}}) \cdot (2 + x)^{'}

(y^{2} e^{x y^{2}} + 4 x^{3}) d x

\frac{4 ( k + 6 )}{k ^{2} + 10 k + 21}

What is expand (2xy)+(y^2-x^2-4)y'(x) ?
The solution to expand (2xy)+(y^2-x^2-4)y'(x) is 2xy+y'(x)y^2-x^2y'(x)-4y'(x)