What is expand 1/((s-3)(s^2+9)) ?

The solution to expand 1/((s-3)(s^2+9)) is 1/(s^3+9s-3s^2-27)

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expand 1/((s-3)(s^2+9))

expand

\frac{1}{( s - 3 ) ( s ^{2} + 9 )}

\frac{1}{s ^{3} + 9 s - 3 s ^{2} - 27}

Solution steps

\frac{1}{( s - 3 ) ( s ^{2} + 9 )}

Expand

(s - 3) (s^{2} + 9) : s^{3} + 9 s - 3 s^{2} - 27

= \frac{1}{s ^{3} + 9 s - 3 s ^{2} - 27}

\frac{- 15 - 2 h}{3 ( 2 + k )}

(1 + e^{2 x})^{4}

\frac{( 2 \cdot π \cdot s )}{( s ^{2} + π ^{2} ) ^{2}}

\frac{1}{3 ( x + 1 ) ^{3}}

(- 4, 4) y (2, - 8)

What is expand 1/((s-3)(s^2+9)) ?
The solution to expand 1/((s-3)(s^2+9)) is 1/(s^3+9s-3s^2-27)