What is expand (4x^2-x+6)/((x^2+2)(x-1)) ?

The solution to expand (4x^2-x+6)/((x^2+2)(x-1)) is (4x^2-x+6)/(x^3-x^2+2x-2)

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expand (4x^2-x+6)/((x^2+2)(x-1))

expand

\frac{4 x ^{2} - x + 6}{( x ^{2} + 2 ) ( x - 1 )}

\frac{4 x ^{2} - x + 6}{x ^{3} - x ^{2} + 2 x - 2}

Solution steps

\frac{4 x ^{2} - x + 6}{( x ^{2} + 2 ) ( x - 1 )}

Expand

(x^{2} + 2) (x - 1) : x^{3} - x^{2} + 2 x - 2

= \frac{4 x ^{2} - x + 6}{x ^{3} - x ^{2} + 2 x - 2}

(w + x \cdot y) (x \cdot, + w) (w + f)

\frac{1}{x ( a x + 1 )}

\frac{1}{( s + 6 ) ( s + 3 )}

(x^{4})^{12}

0.25 (953 - 2 y + x)^{2}

What is expand (4x^2-x+6)/((x^2+2)(x-1)) ?
The solution to expand (4x^2-x+6)/((x^2+2)(x-1)) is (4x^2-x+6)/(x^3-x^2+2x-2)