What is expand 1/((x-a)^3)-1/((x+a)^2) ?

The solution to expand 1/((x-a)^3)-1/((x+a)^2) is 1/(x^3-3ax^2+3a^2x-a^3)-1/(x^2+2ax+a^2)

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expand 1/((x-a)^3)-1/((x+a)^2)

expand

\frac{1}{( x - a ) ^{3}} - \frac{1}{( x + a ) ^{2}}

\frac{1}{x ^{3} - 3 a x ^{2} + 3 a ^{2} x - a ^{3}} - \frac{1}{x ^{2} + 2 a x + a ^{2}}

Solution steps

\frac{1}{( x - a ) ^{3}} - \frac{1}{( x + a ) ^{2}}

(x - a)^{3} = x^{3} - 3 a x^{2} + 3 a^{2} x - a^{3}

= \frac{1}{x ^{3} - 3 a x ^{2} + 3 a ^{2} x - a ^{3}} - \frac{1}{( x + a ) ^{2}}

(x + a)^{2} = x^{2} + 2 a x + a^{2}

= \frac{1}{x ^{3} - 3 a x ^{2} + 3 a ^{2} x - a ^{3}} - \frac{1}{x ^{2} + 2 a x + a ^{2}}

\frac{s + 1}{( s ^{2} + 2 s + 10 ) ^{2}}

f^{'} (1) (x - 1)

\frac{( n + 8 ) ( n + 1 )}{n ( n - 10 )}

\frac{2 - pt}{2 ( 2 - p )}

\frac{15 x ^{2}}{( 2 x ^{3} + 1 ) ^{2}}

What is expand 1/((x-a)^3)-1/((x+a)^2) ?
The solution to expand 1/((x-a)^3)-1/((x+a)^2) is 1/(x^3-3ax^2+3a^2x-a^3)-1/(x^2+2ax+a^2)