What is expand (derivative of 1+x(log_{10}(x+1)))/x ?

The solution to expand (derivative of 1+x(log_{10}(x+1)))/x is (derivative of 1+xlog_{10}(x+x))/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (derivative of 1+x(log_{10}(x+1)))/x

expand

\frac{\frac{d}{d x} ( 1 + x ( lo g _{10} ( x ) + 1 ) )}{x}

\frac{\frac{d}{d x} ( 1 + x lo g _{10} ( x ) + x )}{x}

Solution steps

\frac{\frac{d}{d x} ( 1 + x ( lo g _{10} ( x ) + 1 ) )}{x}

Expand

1 + x (lo g_{10} (x) + 1) : 1 + x lo g_{10} (x) + x

= \frac{\frac{d}{d x} ( 1 + x lo g _{10} ( x ) + x )}{x}

\frac{x ( x + 1 ) ( x + 55 )}{( x - 5 ) ( x + 5 ) ( 5 x + 3 )}

145447 \cdot (1 - ((- 98.07089)^{0.234957}))

\frac{x ^{2} + 15}{( x + 3 ) ( x ^{2} + 3 )}

π (- 4 cos (x) + 4)

(3 e^{t} cos (t) - 3 e^{t} sin (t))^{2}

What is expand (derivative of 1+x(log_{10}(x+1)))/x ?
The solution to expand (derivative of 1+x(log_{10}(x+1)))/x is (derivative of 1+xlog_{10}(x+x))/x