What is expand dx(x+1)(x-1)(x-2) ?

The solution to expand dx(x+1)(x-1)(x-2) is x^3dx-2x^2dx-xdx+2dx

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expand dx(x+1)(x-1)(x-2)

expand

d x (x + 1) (x - 1) (x - 2)

x^{3} d x - 2 x^{2} d x - x d x + 2 d x

Solution steps

d x (x + 1) (x - 1) (x - 2)

Expand

(x + 1) (x - 1) : x^{2} - 1

= d x (x^{2} - 1) (x - 2)

Expand

(x^{2} - 1) (x - 2) : x^{3} - 2 x^{2} - x + 2

= d x (x^{3} - 2 x^{2} - x + 2)

Expand

d x (x^{3} - 2 x^{2} - x + 2) : x^{3} d x - 2 x^{2} d x - x d x + 2 d x

= x^{3} d x - 2 x^{2} d x - x d x + 2 d x

\frac{867 ( 2 + 3 ) 2 - 3}{1960}

\frac{( x - 3 ) ^{2} ( 2 x - 3 )}{( x + 2 ) ( x - 4 )}

\frac{x ^{3} - 6 x ^{2} + 12 x - 8}{x - 2}

\frac{x + 1}{x ^{2} ( x ^{2} + 1 )}

(- 1)^{3}

What is expand dx(x+1)(x-1)(x-2) ?
The solution to expand dx(x+1)(x-1)(x-2) is x^3dx-2x^2dx-xdx+2dx