What is expand cos(x+y)(1+y'(x)) ?

The solution to expand cos(x+y)(1+y'(x)) is cos(x+y)+cos(x+y)y'(x)

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expand cos(x+y)(1+y'(x))

expand

cos (x + y) (1 + y^{'} (x))

cos (x + y) + cos (x + y) y' (x)

Solution steps

cos (x + y) (1 + y^{'} (x))

Apply the distributive law:

a (b + c) = ab + a c

a = cos (x + y), b = 1, c = y^{'} (x)

= cos (x + y) \cdot 1 + cos (x + y) y^{^{'}} (x)

= 1 \cdot cos (x + y) + cos (x + y) y^{^{'}} (x)

Multiply:

1 \cdot cos (x + y) = cos (x + y)

= cos (x + y) + cos (x + y) y^{^{'}} (x)

(2 z - 6 w (z) = 0,) (- z + 2 w (z) = - 8)

\frac{( 49 s ^{2} + 2 ( 7 s + 1 ) )}{s ^{3}}

\frac{5}{( s + 3 ) ^{2} ( s + 1 )}

f (3 x^{2} - 36 x) d x

\frac{q}{( x - a ) ^{2} ( x - b ) ^{2} ( x - c ) ^{2}}

What is expand cos(x+y)(1+y'(x)) ?
The solution to expand cos(x+y)(1+y'(x)) is cos(x+y)+cos(x+y)y'(x)