What is expand ((2x-t)^2)/t ?

The solution to expand ((2x-t)^2)/t is (4x^2)/t-4x+t

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expand ((2x-t)^2)/t

expand

\frac{( 2 x - t ) ^{2}}{t}

\frac{4 x ^{2}}{t} - 4 x + t

Solution steps

\frac{( 2 x - t ) ^{2}}{t}

(2 x - t)^{2} = 4 x^{2} - 4 x t + t^{2}

= \frac{4 x ^{2} - 4 x t + t ^{2}}{t}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 4 x t + t ^{2}}{t} = \frac{4 x ^{2}}{t} - \frac{4 x t}{t} + \frac{t ^{2}}{t}

= \frac{4 x ^{2}}{t} - \frac{4 x t}{t} + \frac{t ^{2}}{t}

Cancel

\frac{4 x t}{t} : 4 x

= \frac{4 x ^{2}}{t} - 4 x + \frac{t ^{2}}{t}

Cancel

\frac{t ^{2}}{t} : t

= \frac{4 x ^{2}}{t} - 4 x + t

\frac{8 ( 2 s + 24 )}{s ^{3} - 4 s ^{2} + 30 s + 333}

\frac{5 x ^{2} - 2 x + 12}{( x + 2 ) ( x - 1 )}

\frac{s ( s + 1 )}{( s ^{2} - 3 s + 15 ) ( s + 2 )}

((\frac{e ^{x} + e ^{- x}}{2}))^{2}

\frac{s ^{3} + 8 s ^{2} + 4 s + 3}{s ^{2} ( s ^{2} + 4 s + 3 )}

What is expand ((2x-t)^2)/t ?
The solution to expand ((2x-t)^2)/t is (4x^2)/t-4x+t