What is expand-((4x+1)(x-2))/2 ?

The solution to expand-((4x+1)(x-2))/2 is -2x^2+(7x)/2+1

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expand-((4x+1)(x-2))/2

expand

- \frac{( 4 x + 1 ) ( x - 2 )}{2}

- 2 x^{2} + \frac{7 x}{2} + 1

Solution steps

- \frac{( 4 x + 1 ) ( x - 2 )}{2}

Expand

(4 x + 1) (x - 2) : 4 x^{2} - 7 x - 2

= - \frac{4 x ^{2} - 7 x - 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 x ^{2} - 7 x - 2}{2} = - (\frac{4 x ^{2}}{2}) - (- \frac{7 x}{2}) - (- \frac{2}{2})

= - (\frac{4 x ^{2}}{2}) - (- \frac{7 x}{2}) - (- \frac{2}{2})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{4 x ^{2}}{2} + \frac{7 x}{2} + \frac{2}{2}

Divide the numbers:

\frac{4}{2} = 2

= - 2 x^{2} + \frac{7 x}{2} + \frac{2}{2}

Apply rule

\frac{a}{a} = 1

= - 2 x^{2} + \frac{7 x}{2} + 1

\frac{50}{( x + y ) ^{3}}

\frac{252 x}{( 4 + x ) ^{5}}

\frac{1 0 ^{43}}{1 0 ^{17}}

\frac{x ^{3} - 3}{( x - 1 ) ^{3}}

3 (3 x + 7)^{8} e x^{3 x} + 24 (3 x + 7)^{7} e^{3 x}

What is expand-((4x+1)(x-2))/2 ?
The solution to expand-((4x+1)(x-2))/2 is -2x^2+(7x)/2+1