What is expand e^{2t}(7sin(t)-cosh(3t)) ?

The solution to expand e^{2t}(7sin(t)-cosh(3t)) is 7e^{2t}sin(t)-e^{2t}cosh(3t)

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expand e^{2t}(7sin(t)-cosh(3t))

expand

e^{2 t} (7 sin (t) - cosh (3 t))

7 e^{2 t} sin (t) - e^{2 t} cosh (3 t)

Solution steps

e^{2 t} (7 sin (t) - cosh (3 t))

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 t}, b = 7 sin (t), c = cosh (3 t)

= e^{2 t} \cdot 7 sin (t) - e^{2 t} cosh (3 t)

= 7 e^{2 t} sin (t) - e^{2 t} cosh (3 t)

n gu l a r (- 2, - \frac{π}{3})

(k + 1)! \cdot (k + 2)

\frac{v ^{3}}{( v ^{2} + 1 ) ( 2 v ^{2} + 1 )}

\frac{( x ^{2} - 3 x + 10 )}{( x - 2 ) ( x ^{2} + 4 )}

((x + 4) ln (x + 4) + 39 x^{10})^{2}

What is expand e^{2t}(7sin(t)-cosh(3t)) ?
The solution to expand e^{2t}(7sin(t)-cosh(3t)) is 7e^{2t}sin(t)-e^{2t}cosh(3t)