What is expand (x^2-2xy+y^2=3)(-1) ?

The solution to expand (x^2-2xy+y^2=3)(-1) is -x^2+2xy-y^2=3

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expand (x^2-2xy+y^2=3)(-1)

expand

(x^{2} - 2 x y + y^{2} = 3) (- 1)

- x^{2} + 2 x y - y^{2} = 3

Solution steps

(x^{2} - 2 x y + y^{2} = 3) (- 1)

= (- 1) (x^{2} - 2 x y + 3 = y^{2})

Distribute parentheses

(- 1) x^{2} + (- 1) (- 2 x y) + (- 1) y^{2} = 3

Apply minus-plus rules

+ (- a) = - a

(- 1) x^{2} - (- 1) \cdot 2 x y + (- 1) y^{2} = 3

Expand

(- 1) x^{2} - (- 1) \cdot 2 x y + (- 1) y^{2} : - x^{2} + 2 x y - y^{2}

- x^{2} + 2 x y - y^{2} = 3

\frac{60 ( s + 6 )}{s ^{3} + 9 s + 168}

\frac{1}{( 5 x + 2 ) ^{2}}

\frac{( - 2 x + 2 ) ( - x ^{2} + 2 x - 4 )}{( x ^{2} - 2 x ) ^{3}}

\frac{( - 2 x + 10 )}{( x + 5 ) ^{2}}

(y = 3, x - 1) (y = 2 x - 4)

What is expand (x^2-2xy+y^2=3)(-1) ?
The solution to expand (x^2-2xy+y^2=3)(-1) is -x^2+2xy-y^2=3