What is expand-3/(x^2(x+3)(x-3)) ?

The solution to expand-3/(x^2(x+3)(x-3)) is -3/(x^4-9x^2)

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expand-3/(x^2(x+3)(x-3))

expand

- \frac{3}{x ^{2} ( x + 3 ) ( x - 3 )}

- \frac{3}{x ^{4} - 9 x ^{2}}

Solution steps

- \frac{3}{x ^{2} ( x + 3 ) ( x - 3 )}

Expand

x^{2} (x + 3) (x - 3) : x^{4} - 9 x^{2}

= - \frac{3}{x ^{4} - 9 x ^{2}}

\frac{4}{( x + 6 ) ( x + h + 6 )}

\frac{\partial}{\partial x} ((z) (4 x^{2} y + 3 y - 5))

\frac{( - 4 x ^{2} + 7 x + 2 ) ( x + 1 )}{2}

\frac{( b - a ) ( a + b )}{2}

\frac{14 v ( 6 v - 5 )}{3}

What is expand-3/(x^2(x+3)(x-3)) ?
The solution to expand-3/(x^2(x+3)(x-3)) is -3/(x^4-9x^2)