What is expand 4x^{4x^2}(2xln(x)+x) ?

The solution to expand 4x^{4x^2}(2xln(x)+x) is 8x^{1+4x^2}ln(x)+4x^{1+4x^2}

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expand 4x^{4x^2}(2xln(x)+x)

expand

4 x^{4 x^{2}} (2 x ln (x) + x)

8 x^{1 + 4 x^{2}} ln (x) + 4 x^{1 + 4 x^{2}}

Solution steps

4 x^{4 x^{2}} (2 x ln (x) + x)

Apply the distributive law:

a (b + c) = ab + a c

a = 4 x^{4 x^{2}}, b = 2 x ln (x), c = x

= 4 x^{4 x^{2}} \cdot 2 x ln (x) + 4 x^{4 x^{2}} x

= 4 \cdot 2 x x^{4 x^{2}} ln (x) + 4 x x^{4 x^{2}}

Simplify

4 \cdot 2 x x^{4 x^{2}} ln (x) + 4 x x^{4 x^{2}} : 8 x^{1 + 4 x^{2}} ln (x) + 4 x^{1 + 4 x^{2}}

= 8 x^{1 + 4 x^{2}} ln (x) + 4 x^{1 + 4 x^{2}}

a b + (x - h)^{2} + k

\frac{\partial}{\partial x} ((f (x, y)) (y^{5} - 3 x y))

\frac{( 8 x ^{6} - 9 ) ^{2}}{576 x ^{6}}

2 (e + \frac{1}{e} - 2)

\frac{y + 2 z - x}{( y + 2 z ) ^{2}}

What is expand 4x^{4x^2}(2xln(x)+x) ?
The solution to expand 4x^{4x^2}(2xln(x)+x) is 8x^{1+4x^2}ln(x)+4x^{1+4x^2}