What is expand ((-x+2)^3)/(12) ?

The solution to expand ((-x+2)^3)/(12) is -(x^3}{12}+\frac{x^2)/2-x+2/3

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expand ((-x+2)^3)/(12)

expand

\frac{( - x + 2 ) ^{3}}{12}

- \frac{x ^{3}}{12} + \frac{x ^{2}}{2} - x + \frac{2}{3}

Solution steps

\frac{( - x + 2 ) ^{3}}{12}

(- x + 2)^{3} = - x^{3} + 6 x^{2} - 12 x + 8

= \frac{( - x ^{3} + 6 x ^{2} - 12 x + 8 )}{12}

Remove parentheses:

(- a) = - a

= \frac{- x ^{3} + 6 x ^{2} - 12 x + 8}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- x ^{3} + 6 x ^{2} - 12 x + 8}{12} = - \frac{x ^{3}}{12} + \frac{6 x ^{2}}{12} - \frac{12 x}{12} + \frac{8}{12}

= - \frac{x ^{3}}{12} + \frac{6 x ^{2}}{12} - \frac{12 x}{12} + \frac{8}{12}

Cancel

\frac{6 x ^{2}}{12} : \frac{x ^{2}}{2}

= - \frac{x ^{3}}{12} + \frac{x ^{2}}{2} - \frac{12 x}{12} + \frac{8}{12}

Divide the numbers:

\frac{12}{12} = 1

= - \frac{x ^{3}}{12} + \frac{x ^{2}}{2} - x + \frac{8}{12}

Cancel

\frac{8}{12} : \frac{2}{3}

= - \frac{x ^{3}}{12} + \frac{x ^{2}}{2} - x + \frac{2}{3}

x (x ln (x) - x)

\frac{\partial}{\partial s} ((f (s, t)) (s^{2} - t^{2}))

\frac{( x + 4 )}{( ( 3 \cdot x + 1 ) \cdot ( x ^{3} + 3 \cdot x ^{2} + 7 \cdot x ) )}

\frac{( x + 3 ) ^{2}}{x}

(6 x) \cdot (2 x)

What is expand ((-x+2)^3)/(12) ?
The solution to expand ((-x+2)^3)/(12) is -(x^3}{12}+\frac{x^2)/2-x+2/3