What is expand 4(x-1-2(2+x)=0) ?

The solution to expand 4(x-1-2(2+x)=0) is -4x-20=0

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expand 4(x-1-2(2+x)=0)

expand

4 (x - 1 - 2 (2 + x) = 0)

- 4 x - 20 = 0

Solution steps

4 (x - 1 - 2 (2 + x) = 0)

= 4 (x - 1 - 2 \cdot 0 = (2 + x))

Distribute parentheses

= 4 x + 4 (- 1) + 4 (- 2 (2 + x) = 0)

Apply minus-plus rules

+ (- a) = - a

4 x - 4 \cdot 1 - 4 \cdot 2 (2 + x) = 0

Expand

4 x - 4 \cdot 1 - 4 \cdot 2 (2 + x) : - 4 x - 20

- 4 x - 20 = 0

(a + 7) (b - 5)^{\circ} (\frac{90}{10 0 ^{\circ}})

x^{7} (a \frac{d y}{d x} + b x^{5} y^{5})

x^{x^{x}} (x^{x} ln (x) (ln (x) + 1) + x^{x - 1})

(13, - 3, 4) x (8, - 4, 3)

(a + b x + c x^{2} + d x^{3} + e x^{4})^{2}

What is expand 4(x-1-2(2+x)=0) ?
The solution to expand 4(x-1-2(2+x)=0) is -4x-20=0