What is the first d/(dy)((x)(x+y)) ?

The first d/(dy)((x)(x+y)) is x

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d/(dy)((x)(x+y))

\frac{d}{d y} ((x) (x + y))

x

Solution steps

\frac{d}{d y} ((x) (x + y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (x + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{d x}{d y} + \frac{d y}{d y})

\frac{d x}{d y} = 0

\frac{d y}{d y} = 1

= x (0 + 1)

Simplify

= x

\frac{( - w ^{2} - 7 w j - 4 )}{( 2 ( - w ^{2} + 7 w j + 12 ) )}

\frac{2 ( 2 x + 1 )}{5}

512 \cdot 996

A (- 3, - 2) B (5, 0)

ln (x) (x - r)