What is expand (((4x^4-1)^2)/(16x^4))+1 ?

The solution to expand (((4x^4-1)^2)/(16x^4))+1 is x^4-1/2+1/(16x^4)+1

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expand (((4x^4-1)^2)/(16x^4))+1

expand

(\frac{( 4 x ^{4} - 1 ) ^{2}}{16 x ^{4}}) + 1

x^{4} - \frac{1}{2} + \frac{1}{16 x ^{4}} + 1

Solution steps

(\frac{( 4 x ^{4} - 1 ) ^{2}}{16 x ^{4}}) + 1

Remove parentheses:

(a) = a

= \frac{( 4 x ^{4} - 1 ) ^{2}}{16 x ^{4}} + 1

(4 x^{4} - 1)^{2} = 16 x^{8} - 8 x^{4} + 1

= \frac{16 x ^{8} - 8 x ^{4} + 1}{16 x ^{4}} + 1

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{8} - 8 x ^{4} + 1}{16 x ^{4}} = \frac{16 x ^{8}}{16 x ^{4}} - \frac{8 x ^{4}}{16 x ^{4}} + \frac{1}{16 x ^{4}}

= \frac{16 x ^{8}}{16 x ^{4}} - \frac{8 x ^{4}}{16 x ^{4}} + \frac{1}{16 x ^{4}} + 1

Cancel

\frac{16 x ^{8}}{16 x ^{4}} : x^{4}

= x^{4} - \frac{8 x ^{4}}{16 x ^{4}} + \frac{1}{16 x ^{4}} + 1

Cancel

\frac{8 x ^{4}}{16 x ^{4}} : \frac{1}{2}

= x^{4} - \frac{1}{2} + \frac{1}{16 x ^{4}} + 1

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What is expand (((4x^4-1)^2)/(16x^4))+1 ?
The solution to expand (((4x^4-1)^2)/(16x^4))+1 is x^4-1/2+1/(16x^4)+1