What is expand (3x-1)(2xe^3+4x^2-5) ?

The solution to expand (3x-1)(2xe^3+4x^2-5) is 6e^3x^2+12x^3-15x-2e^3x-4x^2+5

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expand (3x-1)(2xe^3+4x^2-5)

expand

(3 x - 1) (2 x e^{3} + 4 x^{2} - 5)

6 e^{3} x^{2} + 12 x^{3} - 15 x - 2 e^{3} x - 4 x^{2} + 5

Solution steps

(3 x - 1) (2 x e^{3} + 4 x^{2} - 5)

= (3 x - 1) (2 e^{3} x + 4 x^{2} - 5)

Distribute parentheses

= 3 x \cdot 2 x e^{3} + 3 x \cdot 4 x^{2} + 3 x (- 5) + (- 1) \cdot 2 x e^{3} + (- 1) \cdot 4 x^{2} + (- 1) (- 5)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 3 \cdot 2 e^{3} xx + 3 \cdot 4 x^{2} x - 3 \cdot 5 x - 1 \cdot 2 e^{3} x - 1 \cdot 4 x^{2} + 1 \cdot 5

Simplify

3 \cdot 2 e^{3} xx + 3 \cdot 4 x^{2} x - 3 \cdot 5 x - 1 \cdot 2 e^{3} x - 1 \cdot 4 x^{2} + 1 \cdot 5 : 6 e^{3} x^{2} + 12 x^{3} - 15 x - 2 e^{3} x - 4 x^{2} + 5

= 6 e^{3} x^{2} + 12 x^{3} - 15 x - 2 e^{3} x - 4 x^{2} + 5

\frac{( 1 + sin ( x ) ) ^{2}}{2}

\frac{5 z ^{2} ( z + 2 )}{3 z - 1}

\frac{s}{( s ^{2} + 2 s + 2 ) ( s + 1 )}

t^{5} e^{2 t} d (t - 2)

\frac{- 2 x + h}{( x ^{2} ) ( x + h ) ^{2}}

What is expand (3x-1)(2xe^3+4x^2-5) ?
The solution to expand (3x-1)(2xe^3+4x^2-5) is 6e^3x^2+12x^3-15x-2e^3x-4x^2+5