What is expand ((y+1)(y+8))/((y+2)(y-6)) ?

The solution to expand ((y+1)(y+8))/((y+2)(y-6)) is (y^2+9y+8)/(y^2-4y-12)

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expand ((y+1)(y+8))/((y+2)(y-6))

expand

\frac{( y + 1 ) ( y + 8 )}{( y + 2 ) ( y - 6 )}

\frac{y ^{2} + 9 y + 8}{y ^{2} - 4 y - 12}

Solution steps

\frac{( y + 1 ) ( y + 8 )}{( y + 2 ) ( y - 6 )}

Expand

(y + 2) (y - 6) : y^{2} - 4 y - 12

= \frac{( y + 1 ) ( y + 8 )}{y ^{2} - 4 y - 12}

Expand

(y + 1) (y + 8) : y^{2} + 9 y + 8

= \frac{y ^{2} + 9 y + 8}{y ^{2} - 4 y - 12}

(x^{2} + 2 y) d y

a (4 x - 6 y = - 3)

\frac{x}{( 0.08 - x ) ( 0.06 - x )}

\frac{x}{( a - x ) ^{2}}

\frac{x ( x + 1 ) + 1}{x}

What is expand ((y+1)(y+8))/((y+2)(y-6)) ?
The solution to expand ((y+1)(y+8))/((y+2)(y-6)) is (y^2+9y+8)/(y^2-4y-12)