What is expand ((x^3+1)^3)/9 ?

The solution to expand ((x^3+1)^3)/9 is (x^9)/9+(x^6)/3+(x^3)/3+1/9

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expand ((x^3+1)^3)/9

expand

\frac{( x ^{3} + 1 ) ^{3}}{9}

\frac{x ^{9}}{9} + \frac{x ^{6}}{3} + \frac{x ^{3}}{3} + \frac{1}{9}

Solution steps

\frac{( x ^{3} + 1 ) ^{3}}{9}

(x^{3} + 1)^{3} = x^{9} + 3 x^{6} + 3 x^{3} + 1

= \frac{x ^{9} + 3 x ^{6} + 3 x ^{3} + 1}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{9} + 3 x ^{6} + 3 x ^{3} + 1}{9} = \frac{x ^{9}}{9} + \frac{3 x ^{6}}{9} + \frac{3 x ^{3}}{9} + \frac{1}{9}

= \frac{x ^{9}}{9} + \frac{3 x ^{6}}{9} + \frac{3 x ^{3}}{9} + \frac{1}{9}

Cancel

\frac{3 x ^{6}}{9} : \frac{x ^{6}}{3}

= \frac{x ^{9}}{9} + \frac{x ^{6}}{3} + \frac{3 x ^{3}}{9} + \frac{1}{9}

Cancel

\frac{3 x ^{3}}{9} : \frac{x ^{3}}{3}

= \frac{x ^{9}}{9} + \frac{x ^{6}}{3} + \frac{x ^{3}}{3} + \frac{1}{9}

0.5 \cdot (x^{2} - 4 Lx + 4 L^{2})^{2}

\frac{x ( x + 1 ) ( x + 2 )}{( x + 3 ) ^{3}}

(16900 - 260 a + a^{2}) + 360 a - 21600

(1 - x^{2}) x^{''} - 2 x^{'}

\frac{1}{t ( t - 4 )}

What is expand ((x^3+1)^3)/9 ?
The solution to expand ((x^3+1)^3)/9 is (x^9)/9+(x^6)/3+(x^3)/3+1/9