What is expand (5pi(226sqrt(226)-1))/(27) ?

The solution to expand (5pi(226sqrt(226)-1))/(27) is (1130sqrt(226)pi)/(27)-(5pi)/(27)

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expand (5pi(226sqrt(226)-1))/(27)

expand

\frac{5 π ( 226 226 - 1 )}{27}

\frac{1130 226 π}{27} - \frac{5 π}{27}

Solution steps

\frac{5 π ( 226 226 - 1 )}{27}

Expand

5 π (226226 - 1) : 1130226 π - 5 π

= \frac{1130 226 π - 5 π}{27}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1130 226 π - 5 π}{27} = \frac{1130 226 π}{27} - \frac{5 π}{27}

= \frac{1130 226 π}{27} - \frac{5 π}{27}

\frac{1 - 3 ( s + 2 π )}{( s + 2 π ) ^{2} + 1}

\frac{20}{( ( s ^{2} + 4 ) ( s ^{2} + 3 s + 2 ) )}

i (e^{2 + 3 i} - e^{- 2 - 3 i})

\frac{( x ^{2} + 5 x - 36 ) ( x - 4 )}{x + 7}

What is expand (5pi(226sqrt(226)-1))/(27) ?
The solution to expand (5pi(226sqrt(226)-1))/(27) is (1130sqrt(226)pi)/(27)-(5pi)/(27)