What is e^{(a+1)t}sin((b+2)x)sin^2((c+3)x) ?

The solution to e^{(a+1)t}sin((b+2)x)sin^2((c+3)x) is e^{t(a+1)}sin^2(x(c+3))sin(x(b+2))

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simplify e^{(a+1)t}sin((b+2)x)sin^2((c+3)x)

simplify

e^{(a + 1) t} sin ((b + 2) x) sin^{2} ((c + 3) x)

e^{t (a + 1)} sin^{2} (x (c + 3)) sin (x (b + 2))

Solution steps

e^{(a + 1) t} sin ((b + 2) x) sin^{2} ((c + 3) x)

Could not simplify further

= e^{t (a + 1)} sin^{2} (x (c + 3)) sin (x (b + 2))

\frac{( 8 - x ) ^{5}}{40}

2 e^{- x^{2} - y^{2}} x - 2 e^{- x^{2} - y^{2}} x (x^{2} + 2 y^{2})

\frac{a + b}{( a + b ) ^{2} - 1}

\frac{1}{s ^{2} ( s ^{2} + 2 s + 2 ) - s}

\frac{- 3 s - 5}{2 ( s + 1 ) ( s + 4 ) ( s + 3 )}

What is e^{(a+1)t}sin((b+2)x)sin^2((c+3)x) ?
The solution to e^{(a+1)t}sin((b+2)x)sin^2((c+3)x) is e^{t(a+1)}sin^2(x(c+3))sin(x(b+2))