What is expand ((2x+1)(x-9))/(x+7) ?

The solution to expand ((2x+1)(x-9))/(x+7) is (2x^2-17x-9)/(x+7)

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expand ((2x+1)(x-9))/(x+7)

expand

\frac{( 2 x + 1 ) ( x - 9 )}{x + 7}

\frac{2 x ^{2} - 17 x - 9}{x + 7}

Solution steps

\frac{( 2 x + 1 ) ( x - 9 )}{x + 7}

Expand

(2 x + 1) (x - 9) : 2 x^{2} - 17 x - 9

= \frac{2 x ^{2} - 17 x - 9}{x + 7}

- \frac{2 ( 3 x + 1 )}{x ^{3} ( x + 1 ) ^{5}}

4 (\frac{w + 3}{2})^{2}

\frac{\frac{d}{d x} ( - 4 x + 2 )}{( 3 x - 2 ) ^{2}}

\frac{d ^{3}}{d x ^{3}} ((y) (2 x^{7} - x^{4} - 3 x^{3}))

\frac{( 9 x ^{2} - 3 ) ( x + 3 ) ( x ^{2} + 5 )}{x ^{4}}

What is expand ((2x+1)(x-9))/(x+7) ?
The solution to expand ((2x+1)(x-9))/(x+7) is (2x^2-17x-9)/(x+7)