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Popular >

expand (1+e^x)y'(x)

Solution

expand

(1 + e^{x}) y^{'} (x)

Solution

y' (x) + e^{x} y' (x)

Solution steps

(1 + e^{x}) y^{'} (x)

Apply the distributive law:

a (b + c) = ab + a c

a = y^{'} (x), b = 1, c = e^{x}

= y^{^{'}} (x) 1 + y^{^{'}} (x) e^{x}

= 1 y^{^{'}} (x) + e^{x} y^{^{'}} (x)

Multiply:

1 y^{'} (x) = y^{'} (x)

= y^{^{'}} (x) + e^{x} y^{^{'}} (x)

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Frequently Asked Questions (FAQ)

What is expand (1+e^x)y'(x) ?
The solution to expand (1+e^x)y'(x) is y'(x)+e^xy'(x)