What is expand y'(x)-((x^2+1)(y^2+1))/(x(y-1)) ?

The solution to expand y'(x)-((x^2+1)(y^2+1))/(x(y-1)) is y'(x)-(x^2y^2+x^2+y^2+1)/(xy-x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand y'(x)-((x^2+1)(y^2+1))/(x(y-1))

expand

y^{'} (x) - \frac{( x ^{2} + 1 ) ( y ^{2} + 1 )}{x ( y - 1 )}

y' (x) - \frac{x ^{2} y ^{2} + x ^{2} + y ^{2} + 1}{x y - x}

Solution steps

y^{'} (x) - \frac{( x ^{2} + 1 ) ( y ^{2} + 1 )}{x ( y - 1 )}

\frac{( x ^{2} + 1 ) ( y ^{2} + 1 )}{x ( y - 1 )} = \frac{x ^{2} y ^{2} + x ^{2} + y ^{2} + 1}{x y - x}

= y^{^{'}} (x) - \frac{x ^{2} y ^{2} + x ^{2} + y ^{2} + 1}{x y - x}

\frac{( y - x ) ( y + x ) ( x y ^{'} ( x ) - y )}{x ^{2} y ^{2}}

(x + 1) e^{2}

\frac{6}{s ( s + 2 ) ^{2} ( s + 4 )}

21.36204 (\frac{y ^{5}}{( 2 y + 3 ) ^{2}})^{\frac{1}{3}}

What is expand y'(x)-((x^2+1)(y^2+1))/(x(y-1)) ?
The solution to expand y'(x)-((x^2+1)(y^2+1))/(x(y-1)) is y'(x)-(x^2y^2+x^2+y^2+1)/(xy-x)