What is expand ((3-x)(4-x))/(12) ?

The solution to expand ((3-x)(4-x))/(12) is (x^2)/(12)-(7x)/(12)+1

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expand ((3-x)(4-x))/(12)

expand

\frac{( 3 - x ) ( 4 - x )}{12}

\frac{x ^{2}}{12} - \frac{7 x}{12} + 1

Solution steps

\frac{( 3 - x ) ( 4 - x )}{12}

Expand

(3 - x) (4 - x) : 12 - 7 x + x^{2}

= \frac{12 - 7 x + x ^{2}}{12}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 - 7 x + x ^{2}}{12} = \frac{12}{12} - \frac{7 x}{12} + \frac{x ^{2}}{12}

= \frac{12}{12} - \frac{7 x}{12} + \frac{x ^{2}}{12}

Apply rule

\frac{a}{a} = 1

\frac{12}{12} = 1

= 1 - \frac{7 x}{12} + \frac{x ^{2}}{12}

Rewrite in standard form

= \frac{x ^{2}}{12} - \frac{7 x}{12} + 1

(e^{x} - e^{- x})^{5}

\frac{4 x}{( 3 x ^{2} - 1 ) ^{2}}

\frac{( 2 a ^{2} b ^{4} - a ^{4} b ) ^{3}}{8}

\frac{2 ( s + 1 ) ^{2}}{( s + 2 )}

(5 b, 3, - c) (6, a, 2)

What is expand ((3-x)(4-x))/(12) ?
The solution to expand ((3-x)(4-x))/(12) is (x^2)/(12)-(7x)/(12)+1