What is expand (4x^2-6x)/(3(x-3)(x^2+9)) ?

The solution to expand (4x^2-6x)/(3(x-3)(x^2+9)) is (4x^2-6x)/(3x^3+27x-9x^2-81)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4x^2-6x)/(3(x-3)(x^2+9))

expand

\frac{4 x ^{2} - 6 x}{3 ( x - 3 ) ( x ^{2} + 9 )}

\frac{4 x ^{2} - 6 x}{3 x ^{3} + 27 x - 9 x ^{2} - 81}

Solution steps

\frac{4 x ^{2} - 6 x}{3 ( x - 3 ) ( x ^{2} + 9 )}

Expand

3 (x - 3) (x^{2} + 9) : 3 x^{3} + 27 x - 9 x^{2} - 81

= \frac{4 x ^{2} - 6 x}{3 x ^{3} + 27 x - 9 x ^{2} - 81}

\frac{1}{1 - cos ( 3 0 ^{\circ} )} - \frac{1}{1 + cos ( 3 0 ^{\circ} )}

(2 x - 3 y^{2}) d x + (- y^{3}) d y

\frac{1}{s ^{2} ( t s + 1 )}

\frac{( x + 1 ) d x}{( x ^{2} ( x - 1 ) )}

\frac{\partial}{\partial z} ((x) (x + 2 z))

What is expand (4x^2-6x)/(3(x-3)(x^2+9)) ?
The solution to expand (4x^2-6x)/(3(x-3)(x^2+9)) is (4x^2-6x)/(3x^3+27x-9x^2-81)