What is expand (n!)/((n(n-1))!) ?

The solution to expand (n!)/((n(n-1))!) is (n!)/((n^2-n)!)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (n!)/((n(n-1))!)

expand

\frac{n !}{( n ( n - 1 ) ) !}

\frac{n !}{( n ^{2} - n ) !}

Solution steps

\frac{n !}{( n ( n - 1 ) ) !}

Expand

n (n - 1) : n^{2} - n

= \frac{n !}{( n ^{2} - n ) !}

(x + 3 y - 2 z)^{5}

\frac{e ^{- 2 s}}{( s ^{2} + 1 ) ( s ^{2} + 9 )}

\frac{s ^{2} + s + 16}{( s ^{2} + 16 ) ^{2}}

e^{x^{6} e^{x}} \cdot (x - 4 y = x^{6} e^{x})

x (x^{2} - 1) d x

What is expand (n!)/((n(n-1))!) ?
The solution to expand (n!)/((n(n-1))!) is (n!)/((n^2-n)!)