What is expand ((1+2i)(1+3i))/((3+2i)(x+3i)) ?

The solution to expand ((1+2i)(1+3i))/((3+2i)(x+3i)) is (1+5i+6i^2)/(3x+9i+2ix+6i^2)

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expand ((1+2i)(1+3i))/((3+2i)(x+3i))

expand

\frac{( 1 + 2 i ) ( 1 + 3 i )}{( 3 + 2 i ) ( x + 3 i )}

\frac{1 + 5 i + 6 i ^{2}}{3 x + 9 i + 2 i x + 6 i ^{2}}

Solution steps

\frac{( 1 + 2 i ) ( 1 + 3 i )}{( 3 + 2 i ) ( x + 3 i )}

Expand

(3 + 2 i) (x + 3 i) : 3 x + 9 i + 2 i x + 6 i^{2}

= \frac{( 2 i + 1 ) ( 3 i + 1 )}{3 x + 9 i + 2 i x + 6 i ^{2}}

Expand

(1 + 2 i) (1 + 3 i) : 1 + 5 i + 6 i^{2}

= \frac{1 + 5 i + 6 i ^{2}}{3 x + 9 i + 2 i x + 6 i ^{2}}

\frac{e ^{- 2 s} - e ^{- 4 s}}{( s ^{2} + 1 ) s}

\frac{x ( x - 2 )}{x ^{2} - 9}

(- 2, 6) y (3, - 5)

\frac{5 x ^{3} - 4 x ^{2} - 24}{5 ( x ^{2} + 1 )}

What is expand ((1+2i)(1+3i))/((3+2i)(x+3i)) ?
The solution to expand ((1+2i)(1+3i))/((3+2i)(x+3i)) is (1+5i+6i^2)/(3x+9i+2ix+6i^2)