What is expand 3sin(pi/(12)(t-6))+13 ?

The solution to expand 3sin(pi/(12)(t-6))+13 is -3cos((pit)/(12))+13

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expand 3sin(pi/(12)(t-6))+13

expand

3 sin (\frac{π}{12} (t - 6)) + 13

- 3 cos (\frac{π t}{12}) + 13

Solution steps

3 sin (\frac{π}{12} (t - 6)) + 13

3 sin (\frac{π}{12} (t - 6)) = - 3 cos (\frac{π t}{12})

= - 3 cos (\frac{π t}{12}) + 13

\frac{2 x ^{3} + x ^{2} + 5 x - 2}{( x ^{2} + 1 ) ( x ^{2} + 4 )}

\frac{1}{4 ( x + 7 )}

(- 3 + 3) + (- 33 - 1) i

\frac{3 ( - x + 1 )}{4 ( x - 2 ) ^{2}}

\frac{15 π ( 17 - 5 )}{4}

What is expand 3sin(pi/(12)(t-6))+13 ?
The solution to expand 3sin(pi/(12)(t-6))+13 is -3cos((pit)/(12))+13