What are the solutions to the equation 3w^2-5w=2 ?

The solutions to the equation 3w^2-5w=2 are w=2,w=-1/3

Find the zeros of 3w^2-5w=2

The zeros of 3w^2-5w=2 are w=2,w=-1/3

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3 w^{2} - 5 w = 2

w = 2, w = - \frac{1}{3}

Decimal Notation

w = 2, w = - 0.33333 \dots

Solution steps

3 w^{2} - 5 w = 2

Move

2

to the left side

3 w^{2} - 5 w - 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 2) = 7

w_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 3}, w_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 3}

w = \frac{- ( - 5 ) + 7}{2 \cdot 3} : 2

w = \frac{- ( - 5 ) - 7}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

w = 2, w = - \frac{1}{3}

18 = 2 x^{2}

4 (x + 3) (x + 4) \leq 0

16 y^{2} - 32 y = 48

\frac{4}{3 i}

x^{4} - x^{2}

What are the solutions to the equation 3w^2-5w=2 ?
The solutions to the equation 3w^2-5w=2 are w=2,w=-1/3
Find the zeros of 3w^2-5w=2
The zeros of 3w^2-5w=2 are w=2,w=-1/3