What is expand (2x^3-5x^2+4x)/((x-1)^2) ?

The solution to expand (2x^3-5x^2+4x)/((x-1)^2) is (2x^3-5x^2+4x)/(x^2-2x+1)

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expand (2x^3-5x^2+4x)/((x-1)^2)

expand

\frac{2 x ^{3} - 5 x ^{2} + 4 x}{( x - 1 ) ^{2}}

\frac{2 x ^{3} - 5 x ^{2} + 4 x}{x ^{2} - 2 x + 1}

Solution steps

\frac{2 x ^{3} - 5 x ^{2} + 4 x}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{2 x ^{3} - 5 x ^{2} + 4 x}{x ^{2} - 2 x + 1}

\frac{x ^{2} + 2}{( x + 2 ) ^{2} ( x + 3 )}

(\frac{1}{3 - y})^{3}

\frac{d ^{2}}{d t ^{2}} ((s) (t^{5} - 10 t^{2}))

\frac{6}{x ( 3 + 2 x )}

(\frac{x}{y} - y) d y

What is expand (2x^3-5x^2+4x)/((x-1)^2) ?
The solution to expand (2x^3-5x^2+4x)/((x-1)^2) is (2x^3-5x^2+4x)/(x^2-2x+1)